1.2g of NaCl as used to prepare 200 ml solution , what is the molar concentration of NaCl in solution ?
1.2 * 5 grams/ liter = 6 grams/liter
Na = 11 g/mol
Cl = 35.5 g/mol
Na Cl = 46.5 g/mol
6/46.5 = .129 M
Na is 23 not 11; therefore, molar mass NaCl = about 58.5
mols NaCl = grams/molar mass = 1.2/58.5 = about 0.02 mols.
M = mols/L = about 0.02 mols/0.2 L = ?
OOps sorry, thinking atomic number :(
To determine the molar concentration of NaCl in the solution, we first need to calculate the number of moles of NaCl present.
The molar mass of NaCl (sodium chloride) is 58.44 g/mol.
Given that we have 1.2 g of NaCl, we can use the formula:
moles = mass / molar mass
moles of NaCl = 1.2 g / 58.44 g/mol
moles of NaCl = 0.0206 mol
Now, to find the molar concentration, we use the formula:
molar concentration = moles / volume
Given that the volume of the solution is 200 ml (or 0.2 L), we can calculate the molar concentration:
molar concentration = 0.0206 mol / 0.2 L
molar concentration = 0.103 M
Therefore, the molar concentration of NaCl in the solution is 0.103 M.