Perform the given set operation. Let U = {1,2,3,4,5,6,7,8,9,10}. Enter the answer as a comma-separated list. Enter EMPTY for the empty set.

{3,7,9,} with a bold line over the top

1,3,5,7,9,

the complement of {3,7,9} is all those elements not in {3,7,9}. That is,

{1,2,4,5,6,8,10}

What was your interpretation, that made you come up with your answer?

Steve I have not take algebra since 8th grade, I am now 68 years old and fogot everything

but to answer my question, what did you think about to come up with the answer? Not judging, just trying to understand where you were going.

To perform the given set operation with a bold line over the top, you need to find the complement of the set {3, 7, 9} with respect to the universal set U.

The complement of a set A with respect to a universal set U, denoted as A', is the set of all elements in U that are not in A.

In this case, the universal set U is {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, and the set with a bold line over the top is {3, 7, 9}.

To find the complement of {3, 7, 9} with respect to U:
1. List all the elements in U.
2. Remove any elements that are already in the set {3, 7, 9}.
3. The remaining elements are the complement of {3, 7, 9}.

U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Set with a bold line over the top = {3, 7, 9}

Removing {3, 7, 9} from U:
U - {3, 7, 9} = {1, 2, 4, 5, 6, 8, 10}

Therefore, the complement of {3, 7, 9} with respect to U is {1, 2, 4, 5, 6, 8, 10}.