AgNO3 solutions are often used to plate silver onto other metals.
What is the maximum amount of silver in grams that can be plated out of 4.2L of an AgNO3 solution containing 3.1% Ag by mass?
If the density of the solution is 1.00 g/mL (and it may not be) it has a mass of 4200 grams. That x 0.031 = g Ag in the solution.
To find the maximum amount of silver that can be plated out of the AgNO3 solution, we need to determine the mass of silver in the solution, given the volume and the mass percentage of Ag.
Step 1: Calculate the mass of the AgNO3 solution.
We are given that the volume of the solution is 4.2L. Since the density of water is approximately 1g/mL and assuming the density of the AgNO3 solution is close to that of water, we can convert the volume to mass using the density formula:
Mass = Volume x Density
= 4.2L x 1g/mL
= 4.2kg (1kg = 1000g)
Step 2: Calculate the mass of Ag in the solution.
We are given that the AgNO3 solution contains 3.1% Ag by mass. This means that 3.1 grams of the solution contains 1 gram of Ag. We can set up a proportion to find the mass of Ag in the solution.
(Mass of Ag / Mass of Solution) = (Percentage of Ag / 100)
Mass of Ag = (Percentage of Ag / 100) x Mass of Solution
= (3.1 / 100) x 4200g
= 130.2g
Therefore, the maximum amount of silver that can be plated out of 4.2L of an AgNO3 solution containing 3.1% Ag by mass is 130.2 grams.