Each of two urns contains green balls and red balls. Urn one contains 10 green balls and 8 red balls. Urn two contains 3 green balls and 10 red balls. If a ball is drawn from each urn, what is P(red and red)?
A. 23/18
B. 10/27
C. 40/117
D. 18/31
red from 1st ---> 8/18 = 4/9
red from 2nd ---> 10/13
prob(2res) = (4/9)(10/13) = 40/117
she is right
So what is the answer?!
To find the probability of drawing a red ball from each urn, we need to calculate two separate probabilities.
First, let's calculate the probability of drawing a red ball from Urn one. Urn one contains a total of 10 green balls and 8 red balls, so the probability of drawing a red ball from Urn one is 8/18, which simplifies to 4/9.
Next, let's calculate the probability of drawing a red ball from Urn two. Urn two contains a total of 3 green balls and 10 red balls, so the probability of drawing a red ball from Urn two is 10/13.
To find the probability of both events happening (drawing a red ball from both urns), we multiply the probabilities together. Therefore, the probability of drawing a red ball from both urns is (4/9) * (10/13), which simplifies to 40/117.
Therefore, the answer is C. 40/117.
ebt.mdj vfcqkes
ewfrg
uynthgbfvdcsx