Algebra 2

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How do I solve these inequalities:


-6log (subscript of 4) x > -24

& how do I solve these:




I really don't understand how to solve these so can someone please explain them to me?

  • Algebra 2 -


    you probably meant:
    e^(3x) > e^(x-1), (huge difference from what you typed)
    ln both sides
    ln (e^(3x)) > ln e^(x-1)
    3x > x-1
    2x > -1
    x > -1/2


    -6log (subscript of 4) x > -24
    divide both sides by -6
    log4 x < 4
    x < 4
    but remember we can only take logs of positive numbers, so
    0 < x < 4 , also remember that log(a number between 0 and 1 is negative, and multiplying it by -6 would make the result positive.

    so 1 < x < 256

    check: notice the graph of y = log4 x
    is below y = 4 from 1 to 256

    Now for the equations:
    the way you typed it ...
    8^x = 2
    x = 1/3 , since the cuberoot of 8 is 2

    the way you typed it:
    e^x = 48
    ln both sides
    ln (e^x) = ln 48
    x lne = ln 48
    x = ln 48 , since lne = 1

    divide both sides by 8
    log x = 2
    which means:
    10^2 = x
    x = 100

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