There are two different oxides of copper produced as a result of this reaction. They are copper(I) and copper(II) oxide. If copper is changed to copper(I) oxide the percentage changed in mass is 12%. If copper is changed to copper(II) oxide the percentage change in mass is 25%. What must have been produced as a result of the investigation to give the percentage change in mass you calculated?
What reaction? What change in % did you calculate? I don't get the question?
I don't know I copied the question word for word. He wants to know what was produced and percentage changes. I'm sorry
What is the "mass you calculated" refer to?
To calculate the percentage change in mass, we can use the following formula:
Percentage Change in Mass = (Change in Mass / Original Mass) x 100
Let's denote the original mass of copper as "x".
For the reaction that produces copper(I) oxide, the percentage change in mass is given as 12%. Using the formula, we can write the equation as:
12 = (Change in Mass / x) x 100
Simplifying this equation, we have:
Change in Mass = (12/100) * x
Change in Mass = 0.12x
Similarly, for the reaction that produces copper(II) oxide, the percentage change in mass is given as 25%. Using the formula, we can write the equation as:
25 = (Change in Mass / x) x 100
Simplifying this equation, we have:
Change in Mass = (25/100) * x
Change in Mass = 0.25x
Now, we need to determine what must have been produced in each case to give the respective percentage change in mass.
For the reaction that results in copper(I) oxide, the change in mass is equal to 0.12x. So, 0.12x of a substance must have been produced.
For the reaction that results in copper(II) oxide, the change in mass is equal to 0.25x. So, 0.25x of a substance must have been produced.
In conclusion, for the investigation to give the calculated percentage change in mass, 0.12x and 0.25x of substances must have been produced in each respective reaction to form copper(I) and copper(II) oxide.