(2n + 2)(6n + 1)
Find the product.
using FOIL, you get
(2n)(6n) + (2n)(1) + (2)(6n) + (2)(1)
= 12n^2 + 2n + 12n + 2
= 12n^2 + 14n + 2
To find the product of (2n + 2)(6n + 1),
1. Start by multiplying the first terms of each binomial: 2n * 6n = 12n^2.
2. Next, multiply the outer terms: 2n * 1 = 2n.
3. Then, multiply the inner terms: 2 * 6n = 12n.
4. Finally, multiply the last terms: 2 * 1 = 2.
Putting these terms together, the product is:
12n^2 + 2n + 12n + 2.
To simplify, combine like terms:
The final answer is 12n^2 + 14n + 2.
To find the product of (2n + 2)(6n + 1), you need to multiply each term in the first expression by each term in the second expression.
Start by multiplying the first term in the first expression, which is 2n, by each term in the second expression, 6n and 1:
(2n)(6n) = 12n^2
(2n)(1) = 2n
Now, multiply the second term in the first expression, which is 2, by each term in the second expression, 6n and 1:
(2)(6n) = 12n
(2)(1) = 2
Now, add all the terms you got from the multiplication steps together:
12n^2 + 2n + 12n + 2
Combine like terms:
12n^2 + (2n + 12n) + 2
Simplify:
12n^2 + 14n + 2
Therefore, the product of (2n + 2)(6n + 1) is 12n^2 + 14n + 2.