The volume of 3.96 g of a gas sample at standard conditions it was found to be 1.15 L.Calculate its molecular mass?
well, 1 mole = 22.4 L, so you have
1.15/22.4 moles.
that should help.
Jaco, I worked this for you rour posts down under "chemistry".
To calculate the molecular mass of the gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (usually at standard conditions, so 1 atm)
V = volume (given as 1.15 L)
n = number of moles of gas
R = gas constant (0.0821 L.atm/mol.K)
T = temperature (usually at standard conditions, so 273 K)
We need to determine the value of n, the number of moles of gas. To do this, we can rearrange the ideal gas law equation to solve for n:
n = PV / RT
Substituting the known values:
P = 1 atm
V = 1.15 L
R = 0.0821 L.atm/mol.K
T = 273 K
n = (1 atm)(1.15 L) / (0.0821 L.atm/mol.K)(273 K)
n = 0.0548 mol
Now that we have the number of moles (n), we can calculate the molecular mass (M) using the formula:
M = mass / moles
Given: mass = 3.96 g and moles = 0.0548 mol
M = 3.96 g / 0.0548 mol
M ≈ 72.3 g/mol
Therefore, the molecular mass of the gas sample is approximately 72.3 g/mol.