(0,-2)is the vertex- what is the domain and range???
State the domain and range of the function. (Enter your answers using interval notation.)
not enough information
is your parabola vertical or horizontal?
Was there a graph?
To find the domain and range of a quadratic function given its vertex, we need some additional information. The vertex form of a quadratic function is given by:
f(x) = a(x - h)^2 + k
Where (h, k) represents the vertex of the parabola.
In this case, the given vertex is (0, -2), so we have:
f(x) = a(x - 0)^2 + (-2)
f(x) = ax^2 - 2
To determine the domain of the function, we consider all possible x-values for which the function is defined. Since a quadratic function is defined for all real numbers, the domain is (-∞, ∞).
To determine the range of the function, we observe the y-coordinate of the vertex (-2) and note that the parabola opens upwards. Thus, the range of the function is (-2, ∞) since the function can take any value greater than or equal to -2.
Therefore, the domain is (-∞, ∞) and the range is (-2, ∞) in interval notation.