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Write the balanced chemical equation for each of these reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [Pb(OH)4]2–(aq) complex ion.

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    Just follow the written statements.
    2NaOH(aq) + Pb(NO3)2(aq) --> Pb(OH)2(s) + 2NaNO3(aq)

    Pb(OH)2(s) + 2NaOH(aq) --> [Pb(OH)4]^2-(aq) + 2Na^+(aq). However, this leaves it in ionic form and I think the problem wants it in molecular form so I would make the product Na2Pb(OH)4(aq)

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