Math
posted by Nick .
5x^441x^387x^231x+10=0

I assume you want values of x which solve the equation.
Well, you know the rational roots will be of the form 1,2,5,10 or 1/5,2/5
A little synthetic division shows that x+1 divides twice, so you have
(x+1)(x+1)(5x^251x+10)
Now you can easily see that it is
(x+1)(x+1)(x10)(5x1) = 0
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