1) Find the least number when divide by 25, 45, 60 leaves reminder 20.

2) Find the least number which when divided by 18, 12, 24 leaves a reminder of 16, 10, 22 respectively.
Can U help me to find the answer.

Fine the least natural number which when divided by either 4 or 5 leave a reminder of 1

Sure, I can help you find the answers to these questions.

1) To find the least number that leaves a remainder of 20 when divided by 25, 45, and 60, you can use the concept of the least common multiple (LCM).
Step 1: Find the LCM of 25, 45, and 60.
- Prime factorize each number: 25 = 5^2, 45 = 5 * 3^2, and 60 = 2^2 * 3 * 5.
- Take the highest power of each prime factor: LCM = 2^2 * 3^2 * 5 = 2 * 2 * 3 * 3 * 5 = 180.
Step 2: Subtract the remainder from the LCM: 180 - 20 = 160.
Therefore, the least number that satisfies the given conditions is 160.

2) To find the least number that leaves remainders of 16, 10, and 22 when divided by 18, 12, and 24 respectively, you can again use the concept of the least common multiple (LCM).
Step 1: Find the LCM of 18, 12, and 24.
- Prime factorize each number: 18 = 2 * 3^2, 12 = 2^2 * 3, and 24 = 2^3 * 3.
- Take the highest power of each prime factor: LCM = 2^3 * 3^2 = 2 * 2 * 2 * 3 * 3 = 72.
Step 2: Add the remainders to the LCM: 72 + 16 + 10 + 22 = 120.
Therefore, the least number that satisfies the given conditions is 120.

I hope this helps! Let me know if you have any further questions.