Show that the acceleration is 7.5 m/s2 for a ball that
starts from rest and rolls down a ramp and gains a speed
of 30 m/s in 4 s
a = (V-Vo)/t = (30-0)/4 = 7.5 m/s^2.
What is the acceleration of 7.50 m/s
To show that the acceleration is 7.5 m/s^2 for a ball that starts from rest and rolls down a ramp and gains a speed of 30 m/s in 4 s, we can use the equation for acceleration:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity is 0 m/s (starting from rest), final velocity is 30 m/s, and the time is 4 seconds.
Substituting these values into the equation, we get:
acceleration = (30 m/s - 0 m/s) / 4 s
acceleration = 30 m/s / 4 s
acceleration = 7.5 m/s^2
Therefore, the acceleration is indeed 7.5 m/s^2 for the ball rolling down the ramp.