10t-640/t^2 = 0
Thank you so much for huge help:)))
Assuming the usual carelessness with parentheses, I read this as
(10t-640)/t^2 = 0
a fraction is zero if the numerator is zero. So,
10t-640=0
t = 64
Now, if you meant
10t - (640/t^2) = 0
then clear the fraction and we have
10t^3 - 640 = 0
t^3 = 64
t = 4
Thank you so much:)))
You're welcome! Let's solve the equation 10t - 640/t^2 = 0.
To begin, we can simplify the equation by multiplying both sides by t^2 to eliminate the fraction:
10t * t^2 - 640 * t^2 / t^2 = 0 * t^2
10t^3 - 640 = 0
Next, let's isolate the term with t by adding 640 to both sides:
10t^3 = 640
Now, to solve for t, we need to isolate it. Divide both sides of the equation by 10:
10t^3 / 10 = 640 / 10
t^3 = 64
Finally, we can find the value of t by taking the cube root of both sides:
∛(t^3) = ∛(64)
t = 4
So the solution to the equation 10t - 640/t^2 = 0 is t = 4.