is 3M less or more concentrated than 9M of sulfuric acid? I think that 9M is more concentrated but I wanted to make sure.
thanks
Of course 9M is more concentrated than 3M if both are H2SO4.
M = mols solute/L solution.
So 3M = 3 mols/L = 3*98g/1000 mL = 294g/L
and 9M = 9 mols/L = 9*98g/1000 mL=882g/L
Yes, you are correct. A 9M (nine molar) solution of sulfuric acid is more concentrated than a 3M (three molar) solution. The molarity of a solution represents the number of moles of solute (sulfuric acid in this case) per liter of solution. So, a 9M solution contains a higher concentration of sulfuric acid compared to a 3M solution, indicating that it has more moles of acid dissolved per liter of solution.
To determine which concentration is higher between 3M and 9M of sulfuric acid, you need to understand the concept of molarity. Molarity, denoted as "M," is a measure of the concentration of a solution.
Molarity is calculated by dividing the moles of solute by the volume of the solution (in liters). In this case, a 3M solution of sulfuric acid means that there are 3 moles of sulfuric acid dissolved in 1 liter of solution. Similarly, a 9M solution contains 9 moles of sulfuric acid dissolved in 1 liter of solution.
Since the molarity is a measure of concentration, the higher the molarity value, the more concentrated the solution. Therefore, in this case, a 9M solution of sulfuric acid is indeed more concentrated than a 3M solution.
In summary, your understanding is correct. A 9M solution of sulfuric acid is more concentrated than a 3M solution.