A gas sample in a sealed vial originally at 0.6 atm and 300 K, was heated to 450 K. What other property of the gas has changed? What is the value of this property after heating?

To determine the other property of the gas that has changed, we need to understand the relationship between temperature and pressure of a gas sample.

Charles's Law states that, at constant pressure, the volume of a given amount of gas is directly proportional to its temperature. In other words:

V₁ / T₁ = V₂ / T₂

Where V₁ and T₁ represent the initial volume and temperature of the gas, and V₂ and T₂ represent the final volume and temperature.

In this case, when the gas sample is heated from 300 K to 450 K, we can assume that the volume (V) remains constant since the vial is sealed. Therefore, we can rewrite Charles's Law as:

T₁ / P₁ = T₂ / P₂

Where P₁ and T₁ represent the initial pressure and temperature of the gas, and P₂ and T₂ represent the final pressure and temperature.

Since the pressure (P) is the only remaining variable, we can determine the change in pressure as follows:

(P₁ * T₂) / T₁ = P₂

Substituting the given values into the equation:

(0.6 atm * 450 K) / 300 K = P₂

P₂ = 0.9 atm

So, the other property of the gas that changed is its pressure. After heating, the value of the gas pressure is 0.9 atm.