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Chemistry

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10 mL of 0.1 HCl was added to 9mL of water. 10 mL of that solution was added to another 90 mL of water. The student diluted the sample as above 1 time(s). What is the pH of the solution?

  • Chemistry -

    first dilution: you diluted it to 10/19 of .1M, so it is 10/190 M.
    Then you diluted it 10/100 of its concentration, new concentration 10/1900 M

    the statement <The student diluted the sample as above 1 time(s).>> makes no sense to me, it it means my first paragraph, then the concentration is 10/1900 M

    pH=-log(10/1900)=2.28

    check all that.

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