A bullet is fired horizontally with a speed of 100 m/s aiming at a target 20m away. It misses the target by??

it takes time=.2 seconds to get there, so it falls

h=1/2 g t^2=4.9*.04 meters

To find out how much the bullet misses the target by, we can consider the horizontal motion of the bullet.

We know the initial horizontal velocity (v_x) of the bullet is 100 m/s since it is fired horizontally. The time taken (t) for the bullet to reach the target can be found using the equation:

distance = velocity × time
20m = 100 m/s × t

Solving for t:

t = 20m / 100 m/s
t = 0.2 seconds

Now we can find out how much the bullet misses the target by. Since the bullet travels horizontally at a constant speed, we can calculate the horizontal distance (S) it covers during this time by using the equation:

distance = velocity × time
S = 100 m/s × 0.2 s
S = 20 meters

Therefore, the bullet misses the target by 20 meters.

To determine how far the bullet misses the target, we can use the kinematic equation for horizontal motion:

distance = velocity × time

Since the bullet is fired horizontally, the initial vertical velocity is 0 m/s. The only force acting on the bullet during flight is gravity, which only affects the vertical motion.

The horizontal velocity remains constant throughout the motion, so the time it takes for the bullet to travel 20 m horizontally is given by:

time = distance / velocity

time = 20 m / 100 m/s

time = 0.2 s

Now, let's determine the vertical distance covered by the bullet in 0.2 seconds due to gravity. Assuming no air resistance, we can use the equation:

vertical distance = (1/2) × acceleration × time^2

Since the acceleration due to gravity is approximately 9.8 m/s^2:

vertical distance = (1/2) × 9.8 m/s^2 × (0.2 s)^2

vertical distance = 0.196 m

Therefore, the bullet misses the target by approximately 0.196 meters vertically.