A lightning bolt may carry a current of 1.00 ✕ 104 A for a short time interval. What is the resulting magnetic field 134 m from the bolt? Assume that the bolt extends far above and below the point of observation.
Isn't this Biot-Savat law?
http://dev.physicslab.org/Document.aspx?doctype=3&filename=Magnetism_BiotSavartLaw.xml
To determine the resulting magnetic field at a distance of 134 m from the lightning bolt, we can use the formula for the magnetic field due to a current-carrying wire.
The formula for calculating the magnetic field around a long, straight wire is:
B = (μ₀ * I) / (2π * r)
Where:
B is the magnetic field strength,
μ₀ is the permeability of free space (4π × 10^-7 T·m/A),
I is the current flowing through the wire, and
r is the distance from the wire.
Given:
I = 1.00 ✕ 10^4 A (current)
r = 134 m (distance)
Substituting these values into the formula, we get:
B = (4π × 10^-7 T·m/A * 1.00 ✕ 10^4 A) / (2π * 134 m)
Simplifying the formula, we find:
B = (2 × 10^-7 T·m) / 134
B = 1.49 × 10^-9 T
Therefore, the resulting magnetic field at a distance of 134 m from the lightning bolt is approximately 1.49 × 10^-9 Tesla.