In cat, the gene for black coat is dominant to the gene for white coat. A heterozygous black cat is crossed with a white cat. which of the following is true about the ratio of the offspring from the cross?
black coat white coat
A 1 3
B 3 1
C 4 1
D 4 0
can you please give me an explanation for this question. thanks in advance.
*Black coat, White coat
A. 1,3
B. 3,1
C.4,1
D.4,0
The parents' genotypes are Bw and ww. Use a punnett square.
https://www.google.com/search?client=safari&rls=en&q=punnett+square&ie=UTF-8&oe=UTF-8
thanks for your explanation
To solve this question, you need to understand the basics of genetic inheritance in cats. In this case, the gene for a black coat is dominant to the gene for a white coat.
Let's represent the genes for coat color as follows:
- Black coat gene: B
- White coat gene: b
A heterozygous black cat is represented as Bb, meaning it has one gene for a black coat (B) and one gene for a white coat (b).
When this heterozygous black cat (Bb) is crossed with a white cat (bb), the possible combinations of genes are as follows:
- Offspring 1: Bb (black coat)
- Offspring 2: Bb (black coat)
- Offspring 3: bb (white coat)
- Offspring 4: bb (white coat)
So, from the cross between a heterozygous black cat and a white cat, you get:
- 2 offspring with a black coat (Bb)
- 2 offspring with a white coat (bb)
Therefore, the correct answer is option C: 4 offspring with a black coat and 1 offspring with a white coat.
The ratio of black coat to white coat offspring is 4:1.