Write the net ionic equation for the reaction between potassium hydroxide and copper(I) nitrate.
I presume this forms CuOH and KNO3 but I can't confirm that CuOH or CuNO3 exists.
KOH + CuNO3 --> CuOH + KNO3
OH^- + Cu^+ ==> CuOH.
To write the net ionic equation for the reaction between potassium hydroxide and copper(I) nitrate, we first need to write the balanced chemical equation. The chemical formula for potassium hydroxide is KOH, and the chemical formula for copper(I) nitrate is CuNO3.
The balanced chemical equation for the reaction between potassium hydroxide and copper(I) nitrate is:
2 KOH + CuNO3 -> Cu(OH)2 + 2 KNO3
To find the net ionic equation, we need to eliminate any spectator ions. Spectator ions are ions that are present on both sides of the equation and do not take part in the actual reaction.
In this case, the potassium (K+) and nitrate (NO3-) ions are present on both sides of the equation and do not participate in the reaction. The copper (Cu2+) and hydroxide (OH-) ions are the ones involved in the reaction.
Therefore, the net ionic equation for the reaction between potassium hydroxide and copper(I) nitrate is:
Cu2+ + 2 OH- -> Cu(OH)2
To write the net ionic equation for the reaction between potassium hydroxide (KOH) and copper(I) nitrate (CuNO3), we need to first write the balanced chemical equation.
The formula for potassium hydroxide is KOH, and the formula for copper(I) nitrate is CuNO3. The balanced chemical equation for the reaction is:
2 KOH + CuNO3 -> Cu(OH)2 + 2 KNO3
Now, to write the net ionic equation, we need to separate the soluble ionic compounds into their respective ions and remove the spectator ions, which are the ions that do not participate in the reaction. In this case, the potassium and nitrate ions are spectator ions.
The net ionic equation for the reaction between potassium hydroxide and copper(I) nitrate is:
Cu^+ + 2 OH^- -> Cu(OH)2
Here, the Cu^+ ion from copper(I) nitrate reacts with the OH^- ions from potassium hydroxide to form copper(II) hydroxide (Cu(OH)2).