A grinding wheel 0.3m in diametre has amass of 5kg is rotating at an angular velocity of 2300rev/min.what is the kinetic energy?
KE= 1/2 I w^2
I for a solid disk= 1/2 m r^2
w= rad/sec= 2PI*2300rad/min*1min/60sec
I for a solid disk= 1/2 m r^2
w= rad/sec= 2PI*2300rad/min*1min/60sec