Algebra 2
posted by Omar .
Please help me solve and find the excluded values for this problem. Also please show me the work for this problem I want to learn!F(h) = x^29/x^24x+3

Algebra 2 
Steve
division by zero is not defined. So, when the denominator is zero, f(x) is not defined.
x^24x+3 = (x1)(x3)
so, when x=1 or 3, you are trying to divide by zero. Those values are not part of the domain.
Note that x^29 = (x3)(x+3)
So, for any value except x=3, f(x) = (x+3)/(x1)
The graph available below should help you explore other properties of f(x).
http://www.wolframalpha.com/input/?i=%28x^29%29%2F%28x^24x%2B3%29
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