What linear speed must a 0.0508-kg hula hoop have if its total kinetic energy is to be 0.164 J? Assume the hoop rolls on the ground without slipping.
PE = m*V^2 = 0.164 J.
.0508*V^2 = 0.164
V^2 = 3.228
V = 1.80 m/s.
To find the linear speed of the hula hoop, we can use the formula for kinetic energy:
Kinetic energy (KE) = 1/2 * mass * velocity^2
Given:
Total kinetic energy (KE) = 0.164 J
Mass (m) = 0.0508 kg
We need to find the velocity (v). Rearranging the formula:
v = sqrt(2 * KE / m)
Substituting the given values:
v = sqrt(2 * 0.164 J / 0.0508 kg)
Now, we can calculate the linear speed.