Chemistry
posted by James .
In the spectrum of a specific element, there is a line with a wavelength of 656 nm. Use the Rydberg equation to calculate the value of n for the higher energy Bohr orbit involved in the emission of this light. Assume the value for the lower energy orbit equals 2.

1/wavelength = R*(1/4  1/x^2)
Convert wavelength to meters.
You know R, the 1/4 is 1/2^2. X will be the higher orbit.
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