HOW MANYMOLES OF SULFUR DIOXIDE CAN BE PRODUCED FROM 20.0G OF HYDROGEN SULFIDE?
H2S ==> SO2
mols H2S = 20.0g/molar mass = approx 0.6 but you need to do it more accurately.
There is 1 mol S in H2S and 1 mol S in SO2; therefore, you should be able to produce 0.6 mols SO2.
Then g = mols x molar mass.
Remember to do the math yourself because 0.6 is an estimate.
To determine how many moles of sulfur dioxide can be produced from 20.0g of hydrogen sulfide, we need to use the concept of stoichiometry.
Step 1: Write the balanced chemical equation:
H2S + O2 → SO2 + H2O
Step 2: Determine the molar mass of hydrogen sulfide (H2S) and sulfur dioxide (SO2):
- Molar mass of H2S = 2(1.01) + 32.07 = 34.08 g/mol
- Molar mass of SO2 = 32.07 + 2(16.00) = 64.07 g/mol
Step 3: Calculate the number of moles of hydrogen sulfide in 20.0g:
Number of moles = mass / molar mass
Number of moles of H2S = 20.0g / 34.08 g/mol = 0.586 mol
Step 4: Use the mole ratio from the balanced equation to find the number of moles of sulfur dioxide produced:
From the balanced equation, for every 1 mole of H2S, 1 mole of SO2 is produced.
Therefore, 0.586 mol of H2S will produce 0.586 mol of SO2.
So, 20.0g of hydrogen sulfide can produce 0.586 moles of sulfur dioxide.