X^2-6x+7=0
1.-1.59,4.41
2.-1.59,-4.41
3.1.59,-4.41
4.1.59,4.41
Can someone help?
Anyone?
x = [ 6 +/-sqrt(36 -28) ]/2
= 3 +/- sqrt2
= 1.59 , 4.41 number 4
Certainly! To find the solutions to the given quadratic equation, X^2 - 6x + 7 = 0, you can use the quadratic formula:
X = (-b ± √(b^2 - 4ac)) / (2a),
where a, b, and c are the coefficients of the equation.
In this case, a = 1, b = -6, and c = 7. Plugging these values into the quadratic formula, we get:
X = (-(-6) ± √((-6)^2 - 4(1)(7))) / (2(1)).
Simplifying further:
X = (6 ± √(36 - 28)) / 2,
X = (6 ± √8) / 2.
Now, you can simplify the square root term √8 as follows:
√8 = √(4 × 2) = √4 × √2 = 2√2.
Replacing this value back into the equation:
X = (6 ± 2√2) / 2.
Now, you can divide both the numerator and denominator by 2, which simplifies the equation:
X = 3 ± √2.
So, the solutions to the equation are:
1. X = 3 + √2 ≈ 4.41
2. X = 3 - √2 ≈ 1.59
Therefore, the correct answer is option 2: -1.59, -4.41.