CIE and NIE for 2 K3PO4 + 3 Fe(NO3)2 --> 6 KNO3 + Fe3(PO4)2
I'm guessing but you need to decipher your post. Does CIE and NIE stand for complete and net ionic equation?
To determine the CIE (Complete Ionic Equation) and NIE (Net Ionic Equation) for the given chemical equation:
Step 1: Start by writing the balanced molecular equation, which represents the overall chemical reaction:
2 K3PO4 + 3 Fe(NO3)2 → 6 KNO3 + Fe3(PO4)2
Step 2: Identify the strong electrolytes in the equation. In this case, the strong electrolytes are the compounds that ionize or dissociate completely in aqueous solution. In this equation, K3PO4, Fe(NO3)2, KNO3, and Fe3(PO4)2 are strong electrolytes.
Step 3: Write the balanced ionic equation (CIE) by breaking down the strong electrolytes into their respective ions:
2 K+(aq) + 3 NO3-(aq) + 3 Fe2+(aq) + 6 NO3-(aq) → 6 K+(aq) + 6 NO3-(aq) + Fe3(PO4)2(s)
Step 4: Simplify the equation by eliminating the spectator ions (ions that appear on both sides of the equation without undergoing a change). In this case, the spectator ions are K+ and NO3-. Remove them from both sides of the equation:
3 Fe2+(aq) + 2 PO4^3-(aq) → Fe3(PO4)2(s)
The resulting equation is the net ionic equation (NIE), which represents only the species that are directly involved in the reaction.
In conclusion, the CIE for the given chemical equation is 2 K+(aq) + 3 NO3-(aq) + 3 Fe2+(aq) + 6 NO3-(aq) → 6 K+(aq) + 6 NO3-(aq) + Fe3(PO4)2(s), and the NIE is 3 Fe2+(aq) + 2 PO4^3-(aq) → Fe3(PO4)2(s).