CD has an endpoint at (2,-1)and a midpoint at (8,3). which measure is closest to the length of CD?
the distance from end to end is twice the distance from midpoint to end.
That should get you started. I assume you know how to get the distance between two points. . .
do I use the distance formula
that would be a good guess, if you want to find the distance, eh?
thanks Steve
In triangle ABC ,if A=38degre,B=27degre,b=17m find a and c?
To find the length of CD, we need to determine the distance between its two endpoints. We can use the distance formula to calculate this distance.
The distance formula states that the distance between two points, (x1, y1) and (x2, y2), is given by the following formula:
d = √[(x2 - x1)² + (y2 - y1)²]
In this case, we are given that one endpoint of CD is at (2, -1), and the midpoint is at (8, 3). Let's use these coordinates to calculate the length of CD.
First, we need to determine the coordinates of the other endpoint. Since the midpoint of a line segment divides it into two equal halves, we can find the other endpoint by doubling the x-coordinate and y-coordinate of the midpoint. So, the coordinates of the other endpoint are:
2 * 2 = 4, -1 * 2 = -2
Therefore, the other endpoint of CD is (4, -2).
Now, let's substitute the coordinates of the endpoints into the distance formula:
d = √[(4 - 2)² + (-2 - (-1))²]
= √[(2)² + (-2 + 1)²]
= √[4 + 1]
= √5
So, the length of CD is closest to the square root of 5, which is approximately 2.236.