if you had 0.028 moles of copper sulfide, how many grams would you have?
MOLES=MASS/MR
If that's mols = grams/molar mass, yes.
To find out how many grams of copper sulfide you would have with 0.028 moles, you need to use the molar mass of copper sulfide. Copper sulfide consists of two elements: copper (Cu) and sulfur (S).
1. Find the molar mass of each element:
- Copper (Cu): The atomic mass of copper (Cu) is approximately 63.55 g/mol.
- Sulfur (S): The atomic mass of sulfur (S) is approximately 32.07 g/mol.
2. Calculate the molar mass of copper sulfide:
Multiply the atomic mass of copper by the number of copper atoms (1) present in copper sulfide, and add it to the product of the atomic mass of sulfur and the number of sulfur atoms (1) in copper sulfide.
Molar mass of copper sulfide = (Atomic mass of Cu × number of Cu atoms) + (Atomic mass of S × number of S atoms)
Molar mass of copper sulfide = (63.55 g/mol × 1 atom) + (32.07 g/mol × 1 atom)
3. Add the molar masses of copper and sulfur to obtain the molar mass of copper sulfide:
Molar mass of copper sulfide = 63.55 g/mol + 32.07 g/mol
4. Calculate the mass of copper sulfide:
Mass (in grams) of copper sulfide = Number of moles × Molar mass
Mass of copper sulfide = 0.028 moles × (63.55 g/mol + 32.07 g/mol)
By performing the calculation, you should find that you have approximately 1.95 grams of copper sulfide.