Determine the specific heat of a material if a
34.7 g sample absorbed 45.2 J as it was heated
from 293 K to 318 K.
Answer in units of J/g · K Your answer
must be within ± 2.0%
To determine the specific heat of a material, we can use the equation:
q = mcΔT
Where:
q is the heat absorbed or released by the material (in Joules),
m is the mass of the material (in grams),
c is the specific heat capacity of the material (in J/g·K), and
ΔT is the change in temperature (in Kelvin).
In this case, we are given:
m = 34.7 g (mass of the sample),
q = 45.2 J (heat absorbed),
ΔT = 318 K - 293 K = 25 K (change in temperature).
Now, we can rearrange the equation to solve for c:
c = q / (m * ΔT)
Substituting the given values:
c = 45.2 J / (34.7 g * 25 K)
c = 0.051 J/g·K
Therefore, the specific heat of the material is 0.051 J/g·K.