Calculate the pH of a solution in which
a. [H3O+] = 7.8 x 10-7 M
pH =
b. [H3O+] = 5.1 x 10-6 M
pH =
c. [H3O+] = 6.1 x 10-5 M
pH =
d. [H3O+] = 9.3 x 10-4 M
pH =
I get
8.1
9.5
9.1
6.7
but its wrong please someone help!
To calculate the pH of a solution, you can use the formula:
pH = -log[H3O+]
where [H3O+] is the concentration of hydronium ions in the solution.
Let's solve these step by step:
a. [H3O+] = 7.8 x 10-7 M
Using the formula, substitute the given concentration:
pH = -log(7.8 x 10-7)
Using a calculator:
pH ≈ 6.107
b. [H3O+] = 5.1 x 10-6 M
Using the formula:
pH = -log(5.1 x 10-6)
Using a calculator:
pH ≈ 5.292
c. [H3O+] = 6.1 x 10-5 M
Using the formula:
pH = -log(6.1 x 10-5)
Using a calculator:
pH ≈ 4.212
d. [H3O+] = 9.3 x 10-4 M
Using the formula:
pH = -log(9.3 x 10-4)
Using a calculator:
pH ≈ 3.031
So, the correct answers are:
a. pH ≈ 6.107
b. pH ≈ 5.292
c. pH ≈ 4.212
d. pH ≈ 3.031
Make sure you are using an accurate calculator and checking your calculations.