a gas with a volume of 4.00 L at pressure of 205kPa is allowed to expand to a volume of 12.0L. what is the pressure in the container if the temp remains constant
p1v1 = p2v2
To find the pressure in the container after the gas expands, you can use the combined gas law equation. The combined gas law equation relates the initial and final states of a gas when the temperature remains constant. The equation is as follows:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (what we want to find)
V2 = final volume
T2 = final temperature (which remains constant)
In this case, the initial pressure (P1) is 205 kPa, the initial volume (V1) is 4.00 L, and the final volume (V2) is 12.0 L. Since the temperature remains constant, we can consider T1 and T2 as equal, so we can simplify the equation as follows:
(P1 * V1) = (P2 * V2)
Now, substitute the known values:
(205 kPa * 4.00 L) = (P2 * 12.0 L)
Rearrange the equation to solve for P2:
P2 = (205 kPa * 4.00 L) / 12.0 L
P2 ≈ 68.3 kPa
Therefore, the pressure in the container after the gas expands to a volume of 12.0 L is approximately 68.3 kPa.