posted by Anonymous .
A 47.5-g golf ball is driven from the tee with an initial speed of 41.8 m/s and rises to a height of 34.5 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.88 m below its highest point?
a. KE = 0.5m*V^2 = 0.5m*0 = 0 J.
The velocity is zero at the max. ht.
b. V^2 = Vo^2 + 2g*h
V^2 = 41.8^2 - 19.6*(34.5-8.88)
V^2 = 1245.09
V = 35.29 m/s.