posted by amber .
Sometimes the basicity of a solution is reported using pOH (pOH = -log[OH-]). What is the
a. [OH-] if pOH = 1.90
b. [H3O+] if pOH = 12.94
c. pH if pOH = 9.70
And what is your problem?
a. pOH = -log(OH^-). Substitute and solve.
b. Use pH + pOH = pKw = 14 and solve for pH, then use pH = -log(H3O^+).
c. See b. pH + pOH = pKw = 14