PHysiscs
posted by sam .
Four acrobats of mass 83.5 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 83.5kg acrobat is at the bottom of the tower.
(a) What is the normal force acting on the 83.5kg acrobat?

PHysiscs 
Henry
Fn = m*g = (83.5+68+62+55) * 9.8
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