The sum of three consecutive integers is -204 . What is the largest integer?
1st number ---> x
2nd number -- > x+1
3rd number --> x+2
x+x+1+x+2 = -204
3x = -207
x = -69
largest is -67
or
let the 3 numbers be (x-1) , x , (x+1)
x-1 + x + x+1 = -204
3x = -204
x = -68
largest number is -68+1 = -67
notice that in my second solution, the equation was somewhat easier to solve, but x represented the middle number.
What are four consecutive integers that equal 170
To find the largest integer, we need to set up an equation based on the given information.
Let's assume that the first integer is x. The next two consecutive integers would be (x + 1) and (x + 2).
According to the problem, the sum of these three consecutive integers is -204.
So, the equation becomes:
x + (x + 1) + (x + 2) = -204
Simplifying the equation, we have:
3x + 3 = -204
Subtracting 3 from both sides, we get:
3x = -207
Dividing both sides by 3, we find:
x = -69
Therefore, the largest integer would be the third consecutive integer, which is (x + 2):
-69 + 2 = -67
Hence, the largest integer is -67.
To find the largest integer, we can use algebraic representation and solve for the unknown integers.
Let's assume the first integer is x. Therefore, the second integer would be x + 1 (as they are consecutive), and the third integer would be x + 2.
The sum of these three consecutive integers is -204, so we can write the equation as:
x + (x + 1) + (x + 2) = -204
Simplifying the equation:
3x + 3 = -204
Next, we want to isolate the value of x, so we'll subtract 3 from both sides of the equation:
3x = -207
Now, divide both sides of the equation by 3 to solve for x:
x = -207/3
x = -69
So, the first integer is -69. Now we can find the largest integer by adding 2 to it, since the third integer is x + 2:
Largest integer = -69 + 2 = -67
Therefore, the largest integer is -67.