8.22 g of CuNO3 is dissolved in water to make a 0.590M solution,what is the volume of the solution
CuNO3
molar mass = 63.5 + 14 + 3(16)
= 125.5 grams/mol
8.22 g /125.5 g/mol = .0655 mols of the stuff
.0655 mols/x liters = .59 mols/1 liter
x = .111 liters
To calculate the volume of the solution, we can use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Given:
Molarity (M) = 0.590 M
Amount of CuNO3 = 8.22 g
Step 1: Calculate the moles of CuNO3.
To calculate the moles of CuNO3, we need to know its molar mass. The molar mass of CuNO3 is calculated as follows:
Cu: 63.55 g/mol
N: 14.01 g/mol
O: 16.00 g/mol (x3 atoms)
Total molar mass = 63.55 + 14.01 + (16.00 x 3) = 187.55 g/mol
moles = mass / molar mass
moles = 8.22 g / 187.55 g/mol = 0.0438 mol (rounded to 4 decimal places)
Step 2: Calculate the volume of the solution using the formula.
Molarity (M) = moles / volume
0.590 M = 0.0438 mol / volume
Rearranging the equation:
volume = moles / Molarity
volume = 0.0438 mol / 0.590 M = 0.0742 L (rounded to 4 decimal places)
The volume of the solution is approximately 0.0742 liters.
To find the volume of the solution, you can use the formula:
Volume (V) = Mass (m) / Concentration (C)
First, convert the mass of CuNO3 from grams to moles. To do this, divide the mass by the molar mass of CuNO3.
Molar mass of CuNO3:
Copper (Cu) = 1 atom x 63.55 g/mol = 63.55 g/mol
Nitrogen (N) = 1 atom x 14.01 g/mol = 14.01 g/mol
Oxygen (O) = 3 atoms x 16.00 g/mol = 48.00 g/mol
Total molar mass of CuNO3 = 63.55 + 14.01 + 48.00 = 125.56 g/mol
Now, divide the mass of CuNO3 (8.22 g) by its molar mass to get the number of moles:
Number of moles (n) = Mass (m) / Molar mass (M)
n = 8.22 g / 125.56 g/mol ≈ 0.0655 mol (rounded to 4 decimal places)
Next, use the formula for concentration to find the volume:
Concentration (C) = Number of moles (n) / Volume (V)
Rearranging the formula,
Volume (V) = Number of moles (n) / Concentration (C)
Plugging in the given values:
Concentration (C) = 0.590 M
Number of moles (n) = 0.0655 mol
Volume (V) = 0.0655 mol / 0.590 M
V ≈ 0.1110 L (rounded to 4 decimal places)
Therefore, the volume of the solution is approximately 0.1110 liters.