Probability

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Let X and Y be normal random variables with means 0 and 2, respectively, and variances 1 and 9, respectively. Find the following, using the standard normal table. Express your answers to an accuracy of 4 decimal places.

P(X>0.75)=
P(X≤−1.25)=
Let Z=(Y−3)/4. Find the mean and the variance of Z.

E[Z]=
var(Z)=
P(−1≤Y≤2)=

  • Probability -

    1 P(X>0.75)= 0.2266

    2 P(X≤−1.25)= 0.1056

    Let Z=(Y−3)/4. Find the mean and the variance of Z.
    3. E[Z]= -0.25

    4. var(Z)= 0.5625

    5. P(−1≤Y≤2)= 0.3413

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