Calculus Help and Check
posted by Tanya .
Find dy/dx by implicit differentiation.
x^5(x + y) = y^2(9x − y)
this is what i've got so far but I don't think it is the right answer.
y'= 9y^26x^55x^3y/x^5+9y^218xy

Calculus Help and Check 
Steve
x^5(x + y) = y^2(9x − y)
5x^4(x+y) + x^5(1+y') = 2yy'(9xy) + y^2(9y')
5x^5+5x^4y + x^5 + x^5y' = 18xyy'  2y^2y' + 9y^2 + y^2y'
y'(x^5  18xy  3y^2) = 9y^2 6x^5  5x^4y
y' = (9y^26x^55x^4y)/(x^518xy3y^2)
you were close, but must have messed up some signs somewhere.
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