the length of the fence of a trapezium shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and BC. if BC=54m, CD=19m and AD=42m. find the area of the field.
a = (42+54)/2 * √(19^2 - 12^2)
To find the area of the trapezium shaped field, we'll use the formula:
Area = (1/2) * (sum of parallel sides) * (distance between them)
In this case, the sum of the parallel sides is AD + BC, and the distance between them is AB.
Given information:
AD = 42m
BC = 54m
First, we need to find the value of AB by using the Pythagorean theorem, as AB is perpendicular to AD and BC.
Using Pythagoras, we can calculate the value of AB:
AB^2 = AD^2 - BC^2
AB^2 = 42^2 - 54^2
AB^2 = 1764 - 2916
AB^2 = -1152 (since the result is negative, there is no real value for AB)
Hence, there seems to be an issue in the given dimensions of the trapezium. Please recheck the values or provide additional information to solve the problem accurately.