You roll a number cube numbered from 1 to 6.
P(a prime number)
I think 3/6 or 1/2
P(not a 6) 5/6
P (an even number) 3/6 or 1/2
P (3,6,5,2, or 4) = 5/6
You're correct
1 2 3 4 5 6
primes:
1 3 5
so 3/6 = 1/2
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5/6 YES, you got a NOT !!! :)
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yes
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yes
but 1 is not a prime. It is explicitly excluded from the list of primes.
To calculate the probability of an event, you need to divide the number of favorable outcomes by the total number of possible outcomes.
In this case, the number cube is numbered from 1 to 6, so the total number of possible outcomes is 6. To find the probability of rolling a prime number, you need to determine the number of favorable outcomes (prime numbers) on the cube.
The prime numbers on the cube are 2, 3, and 5. So, the number of favorable outcomes is 3. Therefore, the probability of rolling a prime number is 3/6, which can be simplified to 1/2.
Now, let's calculate the probability of rolling not a 6. Since there is only one 6 on the cube and six total outcomes, there are five favorable outcomes (not rolling a 6). So, the probability of not rolling a 6 is 5/6.
To find the probability of rolling an even number, you need to determine the number of favorable outcomes (even numbers) on the cube. The even numbers on the cube are 2, 4, and 6. So, the number of favorable outcomes is 3. Therefore, the probability of rolling an even number is 3/6 or 1/2.
Lastly, to find the probability of rolling a 3, 6, 5, 2, or 4, you need to determine the number of favorable outcomes (those specific numbers) on the cube. The numbers 3, 6, 5, 2, and 4 are all present on the cube, so there are five favorable outcomes. Therefore, the probability of rolling one of those numbers is 5/6.