Algebra II
posted by herp_derp .
Please help me with this problem.
Simplify.
√(24  10i)

Algebra II 
herp_derp
oh, and also, if it is not too much too ask, please include steps and explanations. ty

Algebra II 
Steve
√(24  10i)
If you want to find a perfect square which equals 2410i, it will have to include 5i, so
(a5i)^2 = 2410i
a^2  10ai  25 = 2410i
Hmmm. Looks like a=1
(15i)^2 = 1  10i  25 = 2410i
So,
√(24  10i) = 15i or 1+5i
Or, if you use polar form, you can see that
r=26
tanθ = 5/12
the square root has
r = √26
tanθ = (1(12/13))/(5/13) = 5
so, we get the same result.
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