Find the surface area of the part of the sphere x^2+y^2+z^2=a^2 inside the circular cylinder x^2+y^2=ay (r=a*sin(θ) in polar coordinates), with a>0.

First time posting on this website, sorry for the lack of details on my attempts but I am really not sure where to start on this problem.

A formula that is useful is A(G)=∫∫√((f_x)^2+(f_y)^2+1)dA

*f_x is the partial derivative with respect to x, f_y is the partial derivative with respect to y

I know that I need to find an equation which should be x^2+y^2+z^2=a^2, and I need to find the limits which is where I am really struggling.

Also according to my professor, I shouldn't have to use any polar coordinate conversions in order to complete this problem, which was my initial approach.

The circle in the x-y plane is

x^2 + (y - a/2)^2 = a^2/4
x^2 = a^2/4 - (4y^2-4ay+a^2)/4 = (y^2-ay)/4

The limits of integration in the x-y plane are

0 < y < a
0 < x < (1/2)√(y^2-ay)

then use symmetry and multiply by 4

To find the surface area of the part of the sphere inside the circular cylinder, we can use the formula for the surface area of a surface of revolution.

First, let's rewrite the equation of the cylinder in terms of y:
x^2 + y^2 = ay
y^2 - ay + x^2 = 0

The cylinder can also be expressed in polar coordinates as r = a*sin(theta).

To find the limits of integration for theta, we need to determine the range of angles that correspond to the part of the sphere inside the cylinder.

One way to do this is to consider the intersection points of the sphere and the cylinder. We can substitute x^2 + y^2 = a*sin(theta)*y into the equation of the sphere x^2 + y^2 + z^2 = a^2:

a*sin(theta)*y + z^2 = a^2

Since the sphere is centered at the origin (0, 0, 0), the intersection points lie on the x-y plane, thus z = 0. Substituting z = 0 into the equation, we have:

a*sin(theta)*y = a^2

Simplifying, we get:

y = a/sin(theta)

The limits of integration for y are the solutions to this equation, which can be found by setting y to 0 and solving for theta:

a/sin(theta) = 0

Since sin(theta) cannot be zero, there are no solutions for this equation. Therefore, the limits of integration for y are 0 to a.

Next, we need to find the limits of integration for r. Since the cylinder is defined as r = a*sin(theta), the limits of integration for r are 0 to a*sin(theta).

Finally, we can calculate the surface area using the formula provided:

A(G) = ∫∫√((f_x)^2+(f_y)^2+1)dA

In this case, f_x = 0, f_y = 1, and dA = r dr d(theta). Plugging these values into the formula, we get:

A(G) = ∫∫√(1^2 + 0^2 + 1)d(r d(theta))
= ∫∫√(2)d(r d(theta))

Integrating with respect to r, we get:

A(G) = ∫∫√(2)d(theta) ∫(0 to a*sin(theta)) r dr

Simplifying:

A(G) = ∫(0 to 2π)√(2) d(theta) ∫(0 to a*sin(theta)) r dr

Evaluating the integrals, we have:

A(G) = 2π ∫(0 to a) r √(2) dr
= 2π[√(2)/2 * r^2] (0 to a)
= π√(2) * a^2

Therefore, the surface area of the part of the sphere inside the circular cylinder x^2 + y^2 = ay is π√(2) * a^2.

To find the surface area of the part of the sphere x^2 + y^2 + z^2 = a^2 inside the circular cylinder x^2 + y^2 = ay, we can use the given formula for the surface area:

A(G) = ∫∫√((f_x)^2 + (f_y)^2 + 1) dA

where f_x and f_y are the partial derivatives of the equation defining the surface, and dA represents the differential area element.

First, let's find f_x and f_y by taking the partial derivatives of x^2 + y^2 + z^2 = a^2:

f_x = 2x
f_y = 2y

Now, let's determine the limits of integration. Since your professor mentioned that polar coordinates are not necessary, we can find the limits in Cartesian coordinates.

The boundary of the circular cylinder is given by x^2 + y^2 = ay. This can be rewritten as y = x^2 / a - x^2.

To find the limits for x, we need to determine the x-values at which the sphere intersects the cylinder. Substituting y = x^2 / a - x^2 into the equation of the sphere, we get:

x^2 + (x^2 / a - x^2)^2 + z^2 = a^2

Simplifying this equation, we find that z^2 = (1 - (1 - 1/a)x^2)^2 - x^2, which represents the vertical profile of the intersection between the sphere and the cylinder.

To find the limits for x, we need to solve this equation for x. However, this is a complicated task and may require numerical methods or approximations. Therefore, this question might be better suited for a computer algebra system or numerical methods.

Once you have determined the limits for x, you can integrate the expression A(G) = ∫∫√((f_x)^2 + (f_y)^2 + 1) dA over those limits to find the surface area of the specified region.

Please note that finding the exact limits for x might be a challenging task, so using numerical methods or approximations might be necessary.