Physics

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A bronze cannon ball with a mass of 4.5 kg is fired vertically from a small cannon and reaches a height of 10.0 m. If the canon is now aimed at an angle 33 degrees above the horizontal, calculate the horizontal distance the cannon ball would travel before it reaches the ground.

  • Physics -

    Not much of a cannon :)
    time to fall to ten meters = time to rise ten meters
    10 = (1/2) g t^2 = 4.9 t^2
    t = 1.43 seconds up or down
    v = Vi - g t
    0 = Vi -9.81 (1.43)
    Vi = 14 m/s muzzle velocity

    now at 33 deg
    u = 14 cos 33 = 11.8 m/s forever
    Vi = 14 sin 33 = 7.62 initial speed up
    How long to top?
    0 = 7.62 - 9.81 t
    t = .777 seconds going up
    so
    time in air = 1.55 s
    so horizontal distance = 11.8*1.55 =18.3 meters

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