if 0.25L of gas is placed in a container at 500K and 104 kPa and the temp is increased to 750K and the pressure is increased to 120kPa what is the new volume of the gas
(P1V1/T1) = (P2V2/T2)
At stp the pressur of a gas was 740 mmhg at 200C and in volume of 500cm3 calculate the volume at stp
To calculate the new volume of the gas, we can use the combined gas law equation:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure
V2 = final volume (what we want to find)
T2 = final temperature
Given:
P1 = 104 kPa
V1 = 0.25 L
T1 = 500 K
P2 = 120 kPa
T2 = 750 K
We can rearrange the equation to solve for V2:
V2 = (P1 * V1 * T2) / (P2 * T1)
Now, let's substitute the given values into the equation and calculate the new volume:
V2 = (104 kPa * 0.25 L * 750 K) / (120 kPa * 500 K)
First, convert the pressures from kPa to Pa (1 kPa = 1000 Pa):
V2 = (104,000 Pa * 0.25 L * 750 K) / (120,000 Pa * 500 K)
Next, simplify the equation and perform the calculations:
V2 = (3.9 * 10^7 Pa * L * K) / (6.0 * 10^7 Pa * K)
V2 = 0.65 L
Therefore, the new volume of the gas is approximately 0.65 liters.