Please Explain thoroughly.
A cell exists in a solution of 10% salt and has an internal concentration of 90% salt. Draw this scenario. Label its tonicity. Show where water would flow.
To thoroughly explain this scenario, we need to understand the concept of tonicity and osmosis.
First, let's draw the scenario. We have a cell placed in a solution with a concentration of 10% salt. The cell itself has an internal concentration of 90% salt.
10% Salt Solution
|
____________________
| |
| Cell |
|________________|
Now, let's label the tonicity. Tonicity refers to the relative concentration of solutes in a solution compared to another solution, typically the cytoplasm of a cell.
In this case, since the cell has a higher concentration of salt (90%) compared to the external solution (10%), the cell is hypertonic to the solution. The solution, on the other hand, is hypotonic to the cell.
Next, we need to determine the direction of water flow. Water tends to move from a hypotonic solution to a hypertonic solution in order to balance the concentration of solutes. This process is called osmosis.
In our scenario, since the solution is hypotonic to the cell, water will flow from the solution into the cell. This movement of water will continue until the concentration of solutes inside and outside the cell reaches an equilibrium.
Therefore, in our diagram, we can add arrows indicating the direction of water flow:
10% Salt Solution
↑
____________________
| |
| ← Cell |
|________________|
The arrow pointing towards the cell indicates the direction of water flow, from the hypotonic solution into the hypertonic cell.
In summary, in this scenario, we have a cell with a higher internal concentration of salt compared to the external solution. This makes the cell hypertonic to the solution. Water will then move from the hypotonic solution into the cell via osmosis until the concentration of solutes inside and outside the cell reaches equilibrium.