A family is building a new house on a rectangular lot of land. The lot measures 7x by 11x and the house will be 2x by 3x. How much land will be left for their yard after the house is built? (1 point)
7x*11x - 2x*3x = 71x^2
IDK if you have the same answer as me I took the test here are my answers BTW I have 18 questions on the test
1. B 10x^4
2. D -3y^5
3. C 6x^2 + 2x + 8 quad trin
4. A 4.7x^2 + 1.6x +3.27
5. D 71x^2
6. D 15h^2 + 26h - 21
7. B 40w^2 + 41w + 10
8. A 12x^2 - 28x + 16
9. B 50TTx^3 + 240TTx^2 + 168TTx + 32TT
10. B 16x^2 - 48xy^3 + 36y^6
11. B (x + 9) and (x - 3)
12. B (x + 6) and (x - 5)
13. D (x - 6y)(x - 4y)
14. C 5x + 4) and (2x - 1)
15. B (5x + 7) and (x - 2)
16. D 45x^2 + 20x + 1
17. C (w + 8)^2
18. D (t + 5)(t - 5)
I know there are a lot of Bs but it should be correct if you have the same test
it took me a long time to type this out if I get you close to a 100% may I get lots of like?
To determine the amount of land that will be left for the yard after the house is built, we need to calculate the area of the lot and subtract the area of the house.
The area of the lot is given by length × width. In this case, the length is 11x and the width is 7x. Thus, the area of the lot is (11x) × (7x) = 77x^2.
The area of the house is also given by length × width. In this case, the length is 3x and the width is 2x. Thus, the area of the house is (3x) × (2x) = 6x^2.
To find the land that will be left for the yard, we subtract the area of the house from the area of the lot: 77x^2 - 6x^2 = 71x^2.
Therefore, the land that will be left for their yard after the house is built is 71x^2.
To find how much land will be left for the yard, we need to subtract the area of the house from the total area of the lot.
First, let's find the area of the lot:
The length of the lot is given as 7x and the width is given as 11x.
The formula for calculating the area of a rectangle is: Area = length x width.
So, the area of the lot = 7x * 11x = 77x^2.
Now, let's find the area of the house:
The length of the house is given as 2x and the width is given as 3x.
The area of the house = 2x * 3x = 6x^2.
Finally, to find the land left for the yard, we subtract the area of the house from the area of the lot:
Land left for the yard = Area of the lot - Area of the house
= 77x^2 - 6x^2
= 71x^2.
Therefore, the family will have 71x^2 of land left for their yard.