how many total atoms are there in the chemical formula B2(CO3)3

3 B₂(CO₃)₃

3 x 2 = 6
3 x 1 x 3 = 9
3 x 3 x 3 = 27
6 + 9 + 27 = 42

14

Hmm, let's see. We have B2(CO3)3, which means we have 2 boron atoms (B), 3 carbonate groups (CO3), and each carbonate group consists of 1 carbon atom (C) and 3 oxygen atoms (O). So, we multiply the number of each type of atom by their respective quantities and add them up: 2 (boron) + 3 (carbonate groups) x (1 carbon + 3 oxygen) = 2 + 9 x (1 + 3) = 2 + 9 x 4 = 2 + 36 = 38 atoms. Ta-da! 38 atoms in total.

To determine the total number of atoms in a chemical formula, you need to count the number of atoms for each element and then multiply it by the corresponding subscript.

In the chemical formula B2(CO3)3, let's break it down step by step:

1. Start with the element B (boron). There are two atoms of boron, indicated by the subscript 2.

2. Move on to the carbonate ion (CO3). This ion consists of three elements: carbon (C), and three oxygen (O) atoms. Since there is a subscript of 3 outside the parenthesis, it applies to every element within the parenthesis. Therefore, we multiply the subscript 3 by the number of atoms in each element within the parenthesis.

- Carbon (C): 3 atoms (3C * 1)
- Oxygen (O): 9 atoms (3O * 3)

3. Now we add up the atoms from both elements:

- Boron (B): 2 atoms
- Carbon (C): 3 atoms
- Oxygen (O): 9 atoms

Finally, we sum them up: 2 + 3 + 9 = 14

Therefore, there are a total of 14 atoms in the chemical formula B2(CO3)3.

B = 2

C = 3
O = 3*3 = 9
total 2 + 3 + 9 = ?