Bill drives his car 10 mph faster on the way home from work than he does going to work in rush hour. If it takes him 1 hrs. going and half an hour returning, how far away is his work?
v
v+10
d = v*1
d = (v+10)*.5
so
v = .5 v + 5
.5 v = 5
v = 10
d = v*1 = 10 miles
Thank you.
You are welcome :)
To solve this problem, we can break it down into two parts. Let's define some variables:
Let's say the speed of Bill's car while going to work is "x" mph.
Therefore, the speed of his car while returning from work is "x + 10" mph since he drives 10 mph faster on the way home.
Now let's calculate the distance to his work:
Distance = Speed × Time
For Bill's trip to work:
Distance to work = x mph × 1 hr
For Bill's trip back home:
Distance from work = (x + 10) mph × 0.5 hr
Since the distance to work is the same as the distance from work, we can set up an equation:
x × 1 = (x + 10) × 0.5
Now we can solve for x:
x = (x + 10) × 0.5
2x = x + 10
x = 10
So Bill's speed while going to work is 10 mph.
Now we can calculate the distance to his workplace using the formula:
Distance = Speed × Time
Distance to work = 10 mph × 1 hr
Distance to work = 10 miles
Therefore, Bill's workplace is 10 miles away.